由2f(x)+f(-x)=X+1······①
将-x代入得2f(-x)+f(x)=-x+1 ·······②
①×2-②得3f(x)=3x+1
∴f(x)=x+1/3
2f(x)+f(-x)=x+1
f(x)+2f(-x)=1-x
4f(x)+2f(-x)=2x+2
3f(x)=3x+1
f(x)=x+(1/3)
解答:
令x=u,得到:2f(u)+f(-u)=u+1
令x=-u,得到:2f(-u)+f*u)=-u+1
解方程组,消去f(-u),得到:3f(u)=3u+1,所以:f(u)(3u+1)/3
所以:f(x)=(3x+1)/3