解1题:
原式=2a-3(a-2b)(1-10a+5b)
=2a-3(a×1-a×10a+a×5b-2b×1+2b×10a-2b×5b)
=2a-3(a-10a²+5ab-2b+20ab-10b²)
=2a-3a+30a²-15ab+6b-60ab+30b²
=-a+30a²-(15ab+60ab)+6b+30b²
=-a+30a²-75ab+6b+30b²
=-1+30×1²-75×1×(-5)+6×(-5)+30×(-5)²
=-1+30+375-30+750
=1124
解2题:
原式=5x²-(x²+5x²-2x-2x²+6x)
=5x²-x²-5x²+2x+2x²-6x
=(5x²-x²-5x²+2x²)+(2x-6x)
=x²-4x
=0.5²-4×0.5
=0.25-2
=-1.75
是啊 带进去 就可以拉啊
把a b 都代入嘛