∫1/[(x^2)(√x)] dx ＝∫x^(-5/2)dx =-2/3x^(-3/2)+C ∫（x^2）√（3-x^3）dx =1/3∫√（3-x^3）dx^3 =-1/2*2/3(3-x^3)^(3/2)+C =-1/3(3-x^3)^(3/2)+C
