(1)∵4x2-3x-1=0,∴4x2-3x=1,∴x2- 3 4 x= 1 4 ,∴x2- 3 4 x+ 9 64 = 1 4 + 9 64 ,∴(x- 3 8 )2= 25 64 ,∴x- 3 8 =± 5 8 ,∴x1=1,x2=- 1 4 ;(2)∵x(x-1)=x,∴x(x-1)-x=0,∴x(x-1-1)=0,即x=0或x-1-1=0,∴x1=0,x2=2.