那很简单了设实部函数为u(x,y),由於f(x,y)=u+iv是解析函数,满足∂u/∂x=∂v/∂y=y对x求不定积分,得u=xy+φ(y)对y求偏导,得∂u/∂y=x+φ'(y)而∂u/∂y=-∂v/∂x=x,∴φ'(y)=0,φ(y)=C∴u=xy+C而f(0,0)=0,解得C=0,∴所求的解析函数为f(x,y)=xy+i(-x²+y²)/2整理得f(z)=z²/2i
