1/(x-3)-2=k/(3-x)两边同时乘以x-3得1-2(x-3)=-k1-2x+6=-k-2x=-k-7 x=(k+7)/2曾根为 3带入 (k+7)/2=3k=-1
1/(x-3)-2=k/(3-x)(1-2x+6)/(x-3)=-k/(x-3)增根为31-6+6=-kk=-1
