f(x)=sin(2x/3+π/3)sin(2x/3+π/3)<0 2kπ<2x/3+π/3<2kπ+π 3kπ-π/2
第一步:设y=2x/3+π/3;第二步:f(y)=sin(y),f(y)<0时,π+2kπ第三步:将y=2x/3+π/3带入π+2kπ