(1) 8.8g(2)80% (1)M(CO2)=M(石)+M(酸)-M(剩余)=25g+101.4g-117.6g=8.8g(2)CaCO3+2HCI=CO2+H2O+CaCI2100 44 x 8.8g x=20g W(CaCO3)=20/25=80%
