解：∵∠AOD-∠BOD＝50∴∠AOD＝∠BOD+50∵直线AB∴∠AOD+∠BOD＝∠AOB＝180∴∠BOD+50+∠BOD＝180∴∠BOD＝65∵∠AOC与∠BOD为对顶角∴∠AOC＝∠BOD＝65∵OE平分∠AOC∴∠AOE＝1/2∠AOC＝32.5∴∠BOE＝180-∠AOE＝180-32.5＝147.5
