1+2sin2次方a-cos2a cos4次方a⼀2-sin4次方a⼀2 要过程滴。。拜托了!

是俩道题哦...
2026年09月21日 22:40
有1个网友回答
网友(1):

1+2*sina*sina-cos2a
=2+(2*sina*sina-1)-cos2a
=2-cos2a-cos2a
=2-2*cos2a

cos(a/2)*cos(a/2)*cos(a/2)*cos(a/2)-sin(a/2)*sin(a/2)*sin(a/2)*sin(a/2)
=(cos(a/2)*cos(a/2)+sin(a/2)*sin(a/2))*(cos(a/2)*cos(a/2)-sin(a/2)*sin(a/2))
=1*cosa
=cosa