(﹣2ab)+(﹣三分之一a的平方b)+5ab-二分之一a的平方b)=3ab-5a^b/6
(-2ab)+(-1/3a^2b+5ab-1/2a^2b)=(-2ab)+(-5/6a^2b+5ab)=-2ab-5/6a^2b+5ab=-5/6a^2b+3ab
(﹣2ab)+(﹣1/3a²b)+5ab-1/2a²b) 算式是不是这样?
解:原式=(-2ab+5ab)+[-(a^2b)/3-(a^2b)/2]=3ab-(5a^2b)/6