∵R1,R2并联∴ 1 R = 1 R1 + 1 R2 , R= R1R2 R1+R2 = 5Ω×4Ω 5Ω+4Ω = 20 9 ΩU=IR=0.9A× 20 9 Ω=2VI1= U R1 = 2V 5Ω =0.4A故答案为:0.4A,2V.