函数f(x)的最小正周期是π
f（-5π/3）=f(π/3) (加上两个周期)
且当x属于[-π/2，0)时 f(-π/3)=sin(-π/3)=-√3/2
奇函数 f(-x)=-f(x)
所以f(-π/3)=-f(π/3)
f(π/3)=-√3/2
f（-5π/3）=-√3/2
f(-x) = - f(x)
f(-5π/3) = - f(5π/3) = - f(π + 2π/3) = - f(2π/3)
= sin(2π/3) = (√3)/2
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