x+1/(x²-x) -1/(3x)=k/(3x-3)(x+1)/{x(x-1)} -1/(3x)=k/{3(x-1)}两边同乘以3x(x-1)：3(x+1)-(x-1) = kx3x+3-x+1=kx(k-2)x=4x=4/(k-2)≠0去分母时两边同乘了3x(x-1)，x≠0，所以增根是x=1x=4/(k-2)=1k=6
不会
