因为a(n+1)/an=(n+2)/n
所以有an/a(n-1)=(n+1)/(n-1)
a(n-1)/a(n-2)=n/(n-2)
a(n-2)/a(n-3)=(n-1)/(n-3)
......
a4/a3=5/3
a3/a2=4/2
a2/a1=3/1
有叠乘知:an/a1=n(n+1)/2,再将a1带入就可以得到:an=n(n+1)/2
a(n+1)/an=(n+2)/n
an/a(n-1)=(n+1)/(n-1)
a(n-1)/a(n-2)=n/(n-2)
a(n-2)/a(n-3)=(n-1)/(n-3)
......
a4/a3=5/3
a3/a2=4/2
a2/a1=3/1
各式相乘
an/a1=n(n+1)/2
an=n^2/2+n/2