化简:x-y⼀x+3y÷x^2-y^2⼀x^2+6xy+9y^2-2y⼀x+y

2026年09月28日 15:58
有1个网友回答
网友(1):

原式=(x-y)/(x+3y)×[(x+3y)^2/(x+y)(x-y)]-2y/(x+y)
=(x+3y)/(x+y)-2y/(x+y)
=(x+3y-2y)/(x+y)
=(x+y)/(x+y)
=1