f(a,b,c)=Sum_{i=1->N}{y(i)-a-b[x(i)]^2 - c[x(i)]^(-2)}^2
0=df(a,b,c)/da = 2Sum_{i=1->N}{y(i)-a-b[x(i)]^2 - c[x(i)]^(-2)}(-1) ...(1)
0=df(a,b,c)/db = 2Sum_{i=1->N}{y(i)-a-b[x(i)]^2 - c[x(i)]^(-2)}{-[x(i)]^2} ...(2)
0=df(a,b,c)/dc = 2Sum_{i=1->N}{y(i)-a-b[x(i)]^2 - c[x(i)]^(-2)}{-[x(i)]^(-2)} ...(3)
解由(1),(2),(3)构成的关于a,b,c的三元一次方程组就可以求得a,b,c的值.