(1) 设公差为da3=a1+2d=-2+2d=4d=3所以an=a1+(n-1)d=-2+3(n-1)=3n-5(2) a4+a5+a6 +a7+a8=(3*4-5)+(3*5-5)+(3*6-5)+(3*7-5)=3*(4+5+6+7)-5*4=66-20=44
(1)d=(a3-a1)/2=3,an=a1+(n-1)d=3n-5(2)原式=S8-S3=(-2)*8+3*(8*(8-1))/2-(-2)*3-3*(3*(3-1))/2=65
1楼最后结果错了,是46