594或1254设x+y=a,xy=b则ab=66,a+b=7(由已知条件得出),所以a=11,b=6;或者a=6,b=11问题=x3(x+y) + x2y2(x+y) + y3(x+y) =(x3 +y3)(x +y)+x2y2(x+y) =(x+y)[(x+y)2 -3xy]+(xy)2(x+y) =a(b2-3b)+b2a带入即可，有什么不明白可以问我
