B： -iz+1=zi-iz-zi=-1-iz(1-i)=-(1+i)z=-(1+i)/(1-i)z=-(1+i)(1+i)/(1-i)(1+i)z=-(i^2+2i+1)/(1-i^2)z=-(2i/2)z=-i 够详细了吧。
(1-i)z=-i-1 ,z=-(i+1)^2/2=-iB
