|x+1|+(1-y)²=0所以x+1=,1-y=0x=-1,y=1原式=(3y³)²-(2x²)²-(4x^4-12x²y³+9y^6)=9y^6-4x^4-4x^4+12x²y³-9y^6=-8x^4+12x²y³=-8+12=4
