f(x)=√2sin(2x-π/4)+1最小正周期T=2π/2=πf(x)max=√2+1由2kπ-π/2≤2x-π/4≤2kπ+π/2得kπ-π/8≤x≤kπ+3π/8单调增区间为[kπ-π/8, kπ+3π/8]由2kπ+π/2≤2x-π/4≤2kπ+3π/2得kπ+3π/8≤x≤kπ+7π/8单调减区间为[kπ+3π/8，kπ+7π/8]
派，最大值为根号2加一求单调根据正玄图像可知
