复数的加减乘除运算
(2+i)³(4-2i)/5i(1+i)=(8+3×4×i+3×2×i²+i³)(4-2i)/5(i-1)=(8+12i-6-i)(4-2i)/5(i-1)=2(2+11i)(2-i)(i+1)/5(i-1)(i+1)=2(2+11i)(i+3)/5(-1-1)=-(2+11i)(i+3)/5=-(35i-5)/5=1-7i
