(x²-y²)(x+y)-(x-y)³ =(x-y)(x+y)(x+y)-(x-y)³=(x-y)[(x+y)²-(x-y)²]=(x-y)(x+y+x-y)(x+y-x+y)=4xy(x-y)
(x²-y²)(x+y)-(x-y)³=(x+y)(x-y)(x+y)-(x-y)³=(x-y)((x+y)²-(x-y)²)=(x-y)(x+y+x-y)(x+y-(x-y))=(x-y)(2x)(2y)=4xy(x-y)