(1)xe^(-x^2)|(0,+∞)
=lim(x->+∞)xe^(-x^2)-0
=lim(x->+∞)x/e^(x^2)
=lim(x->+∞)1/[e^(x^2)*2x]
=0
(2)因为被积函数是偶函数
所以∫(0,+∞)e^(-x^2)dx
=(1/2)*∫(-∞,+∞)e^(-x^2)dx
令A=∫(-∞,+∞)e^(-x^2)dx=∫(-∞,+∞)e^(-y^2)dy
A^2=∫(-∞,+∞)e^(-x^2)dx*∫(-∞,+∞)e^(-y^2)dy
=∫∫e^(-x^2-y^2)dxdy 积分区域为R^2
令x=rcosa,y=rsina,r>=0,0<=a<2π
A^2=∫(0,2π)da*∫(0,+∞)e^(-r^2)*rdr
=(-1/2)*∫(0,2π)da*∫(0,+∞)e^(-r^2)d(-r^2)
=(-1/2)*∫(0,2π)da*e^(-r^2)|(0,+∞)
=(-1/2)*∫(0,2π)da*(-1)
=(1/2)*2π
=π
所以A=√π
∫(0,+∞)e^(-x^2)dx=(√π)/2
(3)综上所述,原式=6*(0-(√π)/2)=-3√π
解: