(3x-4)/(x-2)(x-1)=a/x-1 +b/x-2 (3x-4)/(x-2)(x-1)=[a(x-2)+b(x-1)]/(x-1)(x-2)(3x-4)/(x-2)(x-1)=[(a+b)x-(2a+b)]/(x-1)(x-2)a+b=32a+b=4a=1b=2
