原式等于：
（3X+2Y-2X-3Y)(3X+2Y+2X+3Y)
=(X-Y)(5X+5Y)
=5(X-Y)(X+Y)
...=(3x-3y-2x+2y)(3x+3y+2x+2y) =(x-y)(5x+5y);
5(x+y)(x-y)
乘开以后，合并同类项后
再分解
(3x+2y)^2-(2x+3y)^2
=(9*x^2+12*x*y+4*y^2)-(4*x^2+12*x*y+9*y^2)
=5*x^2-5*y^2
=5*(x+y)(x-y)
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