C++s[0]=&s1什么意思，下面有代码......

class Student{private: int id; string name; string sex; string grade; string major;public: int display(); Student(); Student(int i, string n, string s, string g, string m);Student::Student(){ id = 0; name = ""; sex = ""; grade = ""; major = "";}Student::Student(int i, string n, string s, string g, string m){ id = i; name = n; sex = s; grade = g; major = m;}int Student::display(){ cout << "学号:" <<id<< " "; cout << "姓名:" <<name<< " "; cout << "性别:" <<sex<< " "; cout << "年级:" <<grade<< " "; cout << "专业:" << major << " " << endl;}int main(){Student *s[100];Student s1(130201, "小明", "男", "13级", "计算机科学与技术");s[0] = &s1;s[0]->display();}Student *s[100];是什么？怎么理解？s[0]=&s1;怎么理解？这样有什么用？跟地址有关吗？s[0]->display();怎么理解？怎样执行打印功能？s[0]跟display()又怎样的联系？求详细解答，谢谢