√6+√3+√2 +2=√2(√3+√2)+(√3+√2)=(√3+√2)(√2+1)2√2+√3 +1=(√3+√2)+(√2+1)（2√2+√3 +1）/（√6+√3+√2 +2）=[(√3+√2)+(√2+1)]/(√3+√2)(√2+1)=1/(√2+1)+1/(√3+√2)=(√2+1)(√2-1)/(√2+1)+(√3+√2)(√3-√2)/(√3+√2)=(√2-1)+(√3-√2)=√3-1
