求证:2sin^4 x+3⼀4sin^2 2x+5cos^4 x-cos3xcosx=2+2cos^2 x

2026年09月22日 08:16
有1个网友回答
网友(1):

cos3x=cos(x+2x)=cosxcos2x-sinxsin2x=cosx(cos^2 x-sin^2 x)-2sin^2 xcosx=cos^3 x-3sin^2 xcosx
左边=2sin^4 x+3/4*4sin^2 xcos^2 x+5cos^4 x-cos^4 x+3sin^2 xcos^2 x
=2sin^4 x+4cos^4 x+6sin^2 xcos^2 x
=2(sin^2 x+cos^2 x)(sin^2 x+2cos^2 x)
=2(1+cos^2 x)
=右边