f (x) = x^(k^2+k+2)所以f (2) = 2^(k^2+k+2)f (3) = 3^(k^2+k+2)因为f (2) < f (3)所以2^(k^2+k+2)<3^(k^2+k+2)所以k^2+k+2>0这个题，k取任意值都成立你看下是不是题出错了
