cos4X+sin4X=根号2(sin4x+π/4)1/8(cos4X+sin4X)=根号2/8(sin4x+π/4)
1/8(cos4X+sin4X)=(√2)/8[(√2)/2 cos4X+(√2)/2sin4X)=(√2)/8(sin4X+π/4)
acosX+bsinX的式子只要提出根号A2+B21/8(cos4X+sin4X)就提根号2/8