Z1的共轭复数为Z'=2-3i，Z3=Z'/Z2=(2-3i)/(5-i)=(2-3i)(5+i)/(5-i)(5+i)=(1-i)/2f(Z3)=1-Z3’=1-(1+i)/2=(1-i)/2步骤是这样，应该没错。。。答案。。你再验算验算吧。。我不确定用电脑打会不会出错
=(8-13i)/26
