证明:延长AB至E使BE=BD∵AC=AB+BD∴AE=AC又∵AD是∠BAC的平分线,∴∠BAD=∠DACAD是公共边∴△ADE≌△ADC∴∠AED=∠C又∵BE=BD∴∠AED=∠BDE由三角形性质可知∠ABC=∠BDE+∠AED∴∠ABC=2∠C得证!