x→0+lim |sinx| =lim sinx =0 =sin 0x→0-lim sinx = lim -sinx =0 =sin 0左右都连续。所以连续x→0+lim (|sinx|-|sin0)|/(x-0) =lim sinx/x =1 x→0-lim (|sinx|-|sin0)|/(x-0) = lim -sinx/x =-1左右导数不等，所以不可导
