∫[(1-x)/√(9-4x²)]dx=∫[1/√(9-4x²)]dx-∫[x/√(9-4x²)]dx=(1/3)∫dx/√[(1-(2x/3)²]+(1/8)∫d(9-4x²)/√(9-4x²)=(1/2)∫d(2x/3)/√[1-(2x/3)²]+(1/4)√(9-4x²)+C=(1/2)arcsin(2x/3)+(1/4)√(9-4x²)+C;
见下图：
