解：原式=√(4x^2-4x+1)-√(2x-3)^2 =√（2x-1)^2-√(2x-3)^2 ∵根号下2X-3∴2X-3≥0 x≥1.5∴2x-1＞0原式=根号【（2x-1）^2】-(2x-3) =2x-1-2x+3=2
