32×20-540=100设小道宽x,则(32+20)x-x²=100x²-52x+100=0(x-2)(x-50)=0x=2 x=50(舍)即小道宽2米
32×20-540=100设小道宽x,则(32+20)x-x²=100x²-52x+100=0(x-2)(x-50)=0x=2 x=50