∠B=45°,∠C=60°,AB=6√2 有∠A=180-45-60=75° ∵BC=ABsin∠A/sin∠C （1）BC=6√2*sin75°/sin60° =4√6sin75° =4√6(sin30cos45+cos30sin45) =4√6(√2/4+√6/4) =6+2√3 (2）s=1/2BC*ABsin∠B=1/2(6+2√3)*6√2*√2/2=18+6√3
