答： 原式 =limn->+∞ n*ln[(n+2)/n] =limn->+∞ n*ln(1+2/n) limn->+∞ ln[(1+1/(n/2))^n] =limn->+∞ ln[(1+1/(n/2))^(n/2)*(n/(n/2))] =limn->+∞ ln(e^2) =2
