2(x^2+1/x^2)-3(x+1/x)-1=0设x+1/x=t,x^2+2+1/x^2=t^2,x^2+1/x^2=t^2-22(t^2-2)-3t-1=02t^2-3t-5=0(2t-5)*(t+1)=02t-5=0,t=5/2,则有x+1/x=5/2,x^2-5/2x+1=0,(x-2)*(x-1/2)=0,x1=2,x2=1/2t+1=0,t=-1,则有x+1/x=-1,x^2...
