2^x = 3, 3^y = 2, x = lg3/lg2, y = lg2/lg3 = 1/x1/(x+1) + 1/(y+1) = 1/(x+1) + 1/(1/x+1) = 1/(x+1) + x/(1+x) = 1
1
过程:
x=log23
y=log32
所以xy=1
原式=(x+y+2)/(x+1)(y+1)
=(x+y+2)/(x+y+2)
=1
