化简一下,2014(x-y)+v2014(y-z)+(z-x) = 02014x-2014y+2014y-2014z+z-x = 02014x-2014z+z-x = 02013(x-z) = 0z-x = 0因为x≠y, 所以 x-y≠0;z-x = 0带入(z-y)(z-x)/(x-y)得,(z-y)(z-x)/(x-y)=0看一下还有什么问题。