∵cos(a-π/6)+sina=cosacosπ/6+sinasiπ/6+sina=√3/2cosa+3/2sina=√3(1/2cosa+√3/2sina)=√3sin(a+π/6)=4√3/5即sin(a+π/6）=4/5∴sin(a+7π/6)=sin[π+(a+π/6)]=-sin(a+π/6)=-4/5
你就家那边有精锐吗？我们请教学习有关的都是直接找老师问的、
乱写啥
