∵f(x)=2√3sin(3wx+π/3)(w>0)，在(0,π/3】是增函数又函数f(x)的初相为π/3==>f(0)= 2√3sin(π/3)=3，此时函数处于正弦曲线的上升沿∴只要f(π/3)=2√3sin(ωπ+π/3)<=2√3==>ωπ+π/3<=π/2==>ωπ<=π/6==>ω<=1/6∴ω的最大值是1/6 .
套公式
