a(n+1)+an=6na(n+1) + k1(n+1) + k2 = -(an+k1n+k2)-2k1=6k1=-3-2k2-k1=0-2k2+3=0k2= 3/2a(n+1)+an=6na(n+1) -3(n+1) +3/2 = -(an -3n + 3/2)[a(n+1) -3(n+1) +3/2]/(an -3n + 3/2) = -1(an -3n + 3/2)/(a1-3/2) = (...
