令x=sint,那么dx=cost dt,√(1-x^2)=cost所以原积分=∫ cost/cost *1/sint dt=∫1/sint dt=ln|1/sint -cott| +C,而1/sint=1/x,cott=cost /sint= √(1-x^2) /x故原积分=ln|1/x - √(1-x^2) /x| +C,C为常数...
