( 2n)!/ (2^n * n!) = { 1*2*3*4*5.*(2n-2)*(2n-1)*(2n) } / { 2^n * 1*2*3*4*.*(n-1)*n } = { 1*2*3*4*5.*(2n-2)*(2n-1)*(2n) } / { 2*4*6*8*.*(2n-2)*(2n) } = 1*3*5* .*(2n-1) 证毕
