a+b+c+3=2(根号a+根号b+1+根号c-1) a+b+1+c-1+1+1+1-2(根号a+根号b+1+根号c-1)=（根号a）^2-2*根号a+1+（根号b+1）^2-2*（根号b+1）+1 +（根号c-1）^2-2（根号c-1）+1=(根号a-1)^2+((根号b+1)-1)^2+((根号c-1)-1)^2=...
