x²-6x+9+x²+8x+16-x²+10x-25=17x+24
x²-5x-24=0
a=1,b=-5,c=-24
所以△=b²-4ac=121=11²
所以x=(5±11)/2
x1=-3,x2=8
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(x-3)²+[(x+4)²-(x-5)²]=17x+24
(x-3)²+[(x+4)+(x-5)][(x+4)-(x-5)]=17x+24
(x-3)²+9(2x-1)=17x+24
(x-3)²+18x-9=17x+24
(x-3)²+x-33=0
(x-3)²+(x-3)-30=0
[(x-3)+6][(x-3)-5]=0
x1=-3,x2=8.